64 Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right, which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
Example 1:
Input: grid = [[1,3,1],[1,5,1],[4,2,1]]
Output: 7
Explanation: Because the path 1 → 3 → 1 → 1 → 1 minimizes the sum.
Example 2:
Input: grid = [[1,2,3],[4,5,6]]
Output: 12
走到每个点点最小值为它的值加上上方和左方的最小值,无需关心它具体走那条路。
public int minPathSum(int[][] grid) {
if(grid==null || grid.length==0 || grid[0].length==0) return 0;
for(int i=1;i<grid[0].length;++i){
grid[0][i]+=grid[0][i-1];
}
for(int i=1;i<grid.length;++i){
grid[i][0]+=grid[i-1][0];
}
for(int i=1;i<grid.length;++i){
for(int j=1;j<grid[i].length;++j){
grid[i][j]+=Math.min(grid[i-1][j],grid[i][j-1]);
}
}
return grid[grid.length-1][grid[0].length-1];
}